What is the instantaneous rate of change of $f(x) = e^x$ when $x = 0$ ?

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Answer 1 · 2015-03-29T05:14:31

The instantaneous rate of change is the derivative.

The derivative of $f(x)=e^x$ is $f'(x)=e^x$ .

So, the instantaneous rate of change when $x=0$ is $f'(0)=e^0=1$

What is the instantaneous rate of change of f(x) = e^xf(x) = e^x when x = 0x = 0?