What is the frequency of #f(theta)= sin 12 t - cos 5 t #?

1 Answer
Nghi N.
Jun 28, 2018

Period: #2pi#
Frequency: #1/(2pi)#

Explanation:

Period of sin (12t) --> #(2pi)/12 = pi/6#
Period of cos (5t) --> # (2pi)/5#
Period of f(t) --> least common multiple of #pi/6 and (2pi)/5#

#pi/6# .........x(6)(2) ..... --> #2pi#

(2pi)/5 .........x (5) ......... --> #2pi#

Period of f(t) is #P = 2pi#
Frequency# = 1/P = 1/(2pi)#

Related questions
See all questions in Amplitude, Period and Frequency
Impact of this question
1278 views around the world
You can reuse this answer
Creative Commons License