What is the freezing point of a 1molal and 0.432molal #Zn(H2O)_6 ^(+2)#?
1 Answer
Mar 30, 2017
I'll do the 1 molal solution. You should then be able to do a 0.432 molal solution.
#DeltaT_f = T_f - T_f^"*" = -iK_fm# ,
#T_f# is the freezing point, of course, and#T_f^"*"# is that of water.#i# is the number of ions in solution. We ignore ion pairing for simplicity.#K_f = 1.86^@ "C/m"# #m# is the molality, traditionally in units of#"m"# or "molal".
Clearly, water is not an ion, and the hexahydrate acts as the simple cation in water. Thus,
#DeltaT_f = T_f - 0^@ "C" = color(blue)(T_f)#
#= -(1)(1.86^@ "C/m")("1 m") = color(blue)(-1.86^@ "C")#
