What is the freezing point of a nonionizing antifreeze solution containing 388g ethylene glycol #C_2H_6O_2# and 409 g of water?
1 Answer
Jan 4, 2018
The freezing point =
Explanation:
#∆T_b# =# i*K_f*m#
#∆T_b# = depression in freezing point#i # = vant hoff factor#K_f# = depression constant#m# = molality
mass of ethylene =
molar mass =
no. of moles =
mass of solvent =
molality =
-
#i # =#1# -
#T_i# =# 0^oC# -
#K_f# =#1.86^ oC/m#
Therefore,
#∆T_f = i*K_f*m#
#∆T_f = 1.86^oC/m xx 15.28 m#
#∆T_f = 28.42^o C#
#T_f = 0^oC - 28.42^ oC = -28.42^ oC#