What is the freezing point of a 0.05500 m aqueous solution of NaNO_3NaNO3, if the molal freezing-point-depression constant of water is 1.86°C /m?

1 Answer
Dec 28, 2016

We know the depression of freezing point

DeltaT_f=K_fxxbxxi

Where

K_f->"cryoscopic consrant"=1.86^@"C/m"

b->"molal concentration"=0.055m

i->"Van'tHoff factor"=2" for "NaNO_3 "*"

"*" As NaNO_3 dissociates as follows producing 2 ions per molecule.

NaNO_3rightleftharpoonsNa^+ +NO_3^(-)

So

DeltaT_f=1.86xx0.055xx2~~0.2

So the freezing point of the given aqueous solution will be -0.2^@C