How to find a sloping edge of a rectangular based pyramid? The rectangular based has length 4.8m and width 3m and the height of the pyramid is 4m .

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Answer 1 · 2017-04-11T13:01:00

$4.9m$

Determine the center point of the rectangular base:

$1/2$ of $3m=1.5m$
$1/2$ of $4.8m=2.4m$

The crossing point of the two lines= centre point of the rectangle.

This centre point is also the bottom of the perpendicular height of 4m given.

Draw a line from the corner of the rectangle to the centre of the rectangle.

So: In the horizontal right triangle= adjacent side=1.5m and opposite.side=2.4m

With Pythagoras:

$hypotenuse^2=1.5^2+2.4^2$

hypotenuse $=sqrt(1.5^2+2.4^2)$

hypotenuse $:.=sqrt(8.01$

hypotenuse $:.=2.83m$ also adjacent side of vertical right angle triangle with
Opposite side given $=4m$

So: In the vertical right triangle the hypotenuse = slope of pyramid

$:.Slope^2=2.83^2+4^2$

$:.Slope^2=24.0089^2$

$:.slope=sqrt(24.0089)$

$:.4.9m$ slope of the pyramid