# What is the equation of the normal line of #f(x)= sinx# at #x = pi/8#?

##### 1 Answer

Feb 16, 2017

1.082x+y-1.009, nearly.. See the tangent-inclusive Socratic graph.

#### Explanation:

f at

So, the foot of the normal P is

nearly. at P.

The slope of the normal at P is

Now, the equation to the normal, at P( (0.5837, 0.3927 ), is

1.082x+y-1.009, nearly.

graph{(sinx-y)(1.082x+y-1.01)=0 [-10, 10, -5, 5]}