What is the equation of the line that passes through $(-1,7)$ and is perpendicular to the line that passes through the following points: $(1,3),(-2,6)$ ?

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What is the equation of the line that passes through $(-1,7)$ and is perpendicular to the line that passes through the following points: $(1,3),(-2,6)$ ?

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Answer 1 · 2015-12-24T10:50:29

$y=x+8$

Explanation:

The equation of line passing through (-1,7) is $y-7 = m *(x+1)$ where m is the slope of the line.
The slope of the other perpendicular line, $m1 = (6-3)/(-2-1) = -1$
Condition of perpendicularity is $m*m1 = -1$ so the slope $m = 1$
Thus the equation of the line is $y-7 = 1 * (x+1$ ) or $y= x+8$ (Answer)

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What is the equation of the line that passes through $(-1,7)$ and is perpendicular to the line that passes through the following points: $(1,3),(-2,6)$ ?

1 Answer

Explanation:

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What is the equation of the line that passes through (-1,7)(-1,7) and is perpendicular to the line that passes through the following points: (1,3),(-2,6) (1,3),(-2,6) ?

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Explanation:

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What is the equation of the line that passes through $(-1,7)$ and is perpendicular to the line that passes through the following points: $(1,3),(-2,6)$ ?