What is the equation of the line that passes through $(- 1, 7)$ $(-1,7)$ and is perpendicular to the line that passes through the following points: $(1, 3), (- 2, 6)$ $(1,3),(-2,6)$ ?

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What is the equation of the line that passes through $(- 1, 7)$ $(-1,7)$ and is perpendicular to the line that passes through the following points: $(1, 3), (- 2, 6)$ $(1,3),(-2,6)$ ?

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Answer 1 · 2015-12-24T10:50:29

$y = x + 8$ $y=x+8$

Explanation:

The equation of line passing through (-1,7) is $y - 7 = m \cdot (x + 1)$ $y-7 = m *(x+1)$ where m is the slope of the line.
The slope of the other perpendicular line, $m 1 = \frac{6 - 3}{- 2 - 1} = - 1$ $m1 = (6-3)/(-2-1) = -1$
Condition of perpendicularity is $m \cdot m 1 = - 1$ $m*m1 = -1$ so the slope $m = 1$ $m = 1$
Thus the equation of the line is $y - 7 = 1 \cdot (x + 1$ $y-7 = 1 * (x+1$ ) or $y = x + 8$ $y= x+8$ (Answer)

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What is the equation of the line that passes through $(- 1, 7)$ $(-1,7)$ and is perpendicular to the line that passes through the following points: $(1, 3), (- 2, 6)$ $(1,3),(-2,6)$ ?

1 Answer

Explanation:

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What is the equation of the line that passes through (−1,7)(-1,7) and is perpendicular to the line that passes through the following points: (1,3),(−2,6)(1,3),(-2,6) ?

1 Answer

Explanation:

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What is the equation of the line that passes through $(- 1, 7)$ $(-1,7)$ and is perpendicular to the line that passes through the following points: $(1, 3), (- 2, 6)$ $(1,3),(-2,6)$ ?