# What is the equation of the line tangent to # f(x)=e^(x^2+x) # at # x=0 #?

##### 1 Answer

Apr 27, 2018

#### Explanation:

To find the point (0,y) which lies on the tangent We **substitute in the function with the value**

So **the point is **

to find the slope

**Substitute** with the point

**The Equation of a Straight Line**

**Substitute**