What is the slope of a line tangent to the curve $3 y^{2} - 2 x^{2} = 1$ $3y^2-2x^2=1$ ?

Question

What is the slope of a line tangent to the curve $3 y^{2} - 2 x^{2} = 1$ $3y^2-2x^2=1$ ?

1 Answer

Impact of this question

18656 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-30T16:15:40

The slope of the tangent line is $\frac{2 x}{3 y}$ $(2x)/(3y)$ .

Explanation:

We have:

$6 y (\frac{d y}{d x}) - 4 x = 0$ $6y(dy/dx) - 4x = 0$

$6 y (\frac{d y}{d x}) = 4 x$ $6y(dy/dx) = 4x$

$\frac{d y}{d x} = \frac{4 x}{6 y}$ $dy/dx= (4x)/(6y)$

$\frac{d y}{d x} = \frac{2 x}{3 y}$ $dy/dx = (2x)/(3y)$

Hopefully this helps!

Science

Math

Humanities

... and beyond

What is the slope of a line tangent to the curve $3 y^{2} - 2 x^{2} = 1$ $3y^2-2x^2=1$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What is the slope of a line tangent to the curve 3y2−2x2=13y^2-2x^2=1?

1 Answer

Explanation:

Related questions

Impact of this question

What is the slope of a line tangent to the curve $3 y^{2} - 2 x^{2} = 1$ $3y^2-2x^2=1$ ?