What is the slope of a line tangent to the curve 3y^2-2x^2=13y2−2x2=1?
1 Answer
Mar 30, 2018
The slope of the tangent line is
Explanation:
We have:
6y(dy/dx) - 4x = 06y(dydx)−4x=0
6y(dy/dx) = 4x6y(dydx)=4x
dy/dx= (4x)/(6y)dydx=4x6y
dy/dx = (2x)/(3y)dydx=2x3y
Hopefully this helps!