What is the equation of the line perpendicular to #y=9/5x # that passes through # (-12,8) #?

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Answer 1 · 2016-02-28T03:59:28

#y-8=-5/9(x--12)#

If the line is perpendicular to #y=9/5x# then we have to use the slope which is negative reciprocal of 9/5.

that is #m=-1/(9/5)=-5/9#

passing thru the point #(-12, 8)#

Point-Slope Form

#(y-y_1)=m(x-x_1)#

#y-8=-5/9(x--12)#

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