What is the equation of the line perpendicular to $y=9/5x$ that passes through $(-12,8)$ ?

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Answer 1 · 2016-02-28T03:59:28

$y-8=-5/9(x--12)$

If the line is perpendicular to $y=9/5x$ then we have to use the slope which is negative reciprocal of 9/5.

that is $m=-1/(9/5)=-5/9$

passing thru the point $(-12, 8)$

Point-Slope Form

$(y-y_1)=m(x-x_1)$

$y-8=-5/9(x--12)$

God bless...I hope the explanation is useful..

What is the equation of the line perpendicular to y=9/5x y=9/5x that passes through (-12,8) (-12,8) ?