What is the equation of the line perpendicular to $y = \frac{9}{5} x$ $y=9/5x$ that passes through $(- 12, 8)$ $(-12,8)$ ?

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Answer 1 · 2016-02-28T03:59:28

$y - 8 = - \frac{5}{9} (x - - 12)$ $y-8=-5/9(x--12)$

If the line is perpendicular to $y = \frac{9}{5} x$ $y=9/5x$ then we have to use the slope which is negative reciprocal of 9/5.

that is $m = - \frac{1}{\frac{9}{5}} = - \frac{5}{9}$ $m=-1/(9/5)=-5/9$

passing thru the point $(- 12, 8)$ $(-12, 8)$

Point-Slope Form

$(y - y_{1}) = m (x - x_{1})$ $(y-y_1)=m(x-x_1)$

$y - 8 = - \frac{5}{9} (x - - 12)$ $y-8=-5/9(x--12)$

God bless...I hope the explanation is useful..

What is the equation of the line perpendicular to y=9/5x y=95xy=9/5x that passes through (-12,8) (−12,8) (-12,8) ?