What is the equation of the line perpendicular to y=6/7x y=67x that passes through (1,-3) (1,−3)?

1 Answer
Nallasivam V
May 24, 2016

y=-7/6x-11/6y=−76x−116

Explanation:

Given -

y=6/7xy=67x
Slope of the given line m_1=6/7m1=67

Two lines are perpendicular if -

m_1 xx m_2=-1m1×m2=−1

m_2m2 is the slope of the required line.

6/7 xx m_2=-167×m2=−1
m_2=-1 xx 7/6=-7/6m2=−1×76=−76

Equation of the perpendicular line -

y=mx+cy=mx+c
-3=-7/6(1)+c−3=−76(1)+c
c-7/6=-3c−76=−3
c=-3 +7/6=(-18+7)/6=-11/6c=−3+76=−18+76=−116

y=-7/6x-11/6y=−76x−116

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