What is the equation of the line perpendicular to $y=6/7x$ that passes through $(1,-3)$ ?

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Answer 1 · 2016-05-24T04:50:07

$y=-7/6x-11/6$

Given -

$y=6/7x$
Slope of the given line $m_1=6/7$

Two lines are perpendicular if -

$m_1 xx m_2=-1$

$m_2$ is the slope of the required line.

$6/7 xx m_2=-1$
$m_2=-1 xx 7/6=-7/6$

Equation of the perpendicular line -

$y=mx+c$
$-3=-7/6(1)+c$
$c-7/6=-3$
$c=-3 +7/6=(-18+7)/6=-11/6$

$y=-7/6x-11/6$

What is the equation of the line perpendicular to y=6/7x y=6/7x that passes through (1,-3) (1,-3) ?