What is the equation of the line perpendicular to $y=-22/3x$ that passes through $(-1,9)$ ?

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Answer 1 · 2015-12-03T11:57:16

$y= 3/22 x + 201/22$

Two lines with slopes $m_1$ and $m_2$ are perpendicular if $m_1=-1/m_2$

So, since the slope of $y=-22/3 x$ is $-22/3$ , the perpendicular slope is $3/22$ .

Once we know the slope and a point $(x_0,y_0)$ the equation for the line with that slope passing through that point is

$y-y_0 = m(x-x_0)$

Plugging your values, we have

$y-9 = 3/22(x+1)$

$y=3/22x +3/22+9 = 3/22 x + 201/22$

What is the equation of the line perpendicular to y=-22/3x y=-22/3x that passes through (-1,9) (-1,9) ?