What is the equation of the line perpendicular to #y=-22/3x # that passes through # (-1,9) #?

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Answer 1 · 2015-12-03T11:57:16

#y= 3/22 x + 201/22#

Two lines with slopes #m_1# and #m_2# are perpendicular if #m_1=-1/m_2#

So, since the slope of #y=-22/3 x# is #-22/3#, the perpendicular slope is #3/22#.

Once we know the slope and a point #(x_0,y_0)# the equation for the line with that slope passing through that point is

#y-y_0 = m(x-x_0)#

Plugging your values, we have

#y-9 = 3/22(x+1)#

#y=3/22x +3/22+9 = 3/22 x + 201/22#