# What is the equation of the line normal to #f(x)= x^2sin^2(2x) # at #x=pi/6#?

##### 1 Answer

#### Explanation:

Let's begin by finding the y coordinate corresponding to the given x coordinate:

The slope, n, of the normal line is:

To obtain the slope of the tangent line, we must compute the first derivative:

Evaluate at

Using the point-slope form of the equation of a line: