What is the equation of the line between #(3,16)# and #(2,4)#?

1 Answer
Alan P.
Jan 4, 2016

In slope-point form: #(y-4)=12(x-2)#

In standard form: #12x-y=20#

Explanation:

The slope between the points #(3,16)# and #(2,4)# is
#color(white)("XXX")m=(Delta y)/(Delta x)= (16-4)/(3-2) = 12#

The general slope-point form for a line with slope #m# through a point #(barx,bary)# is
#color(white)("XXX")(y-bary)=m(x-barx)#

Using the slope determined above and the point #(2,4)# (either point could have been used and would generate equivalent results)
#color(white)("XXX")(y-4)=12(x-2)#

Conversion to standard form
#color(white)("XXX")Ax+By=C#
only requires simple common operations.

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