What is the equation for a line that passes through the point (-1,8) and lies only quadrants I,II,and IV on a graph?

1 Answer
Tony B
Mar 24, 2016

y=-x^3+7

Explanation:

color(brown)("Note that the question does not state 'straight line'.")

Using y=-x^3+c

Given points (-1,8) => y=-x^3+c" "->" " 8=-(-1)^3+c

=>8-1=c =7

Thus y=-x^3+c" "->" "y=-x^3+7

Tony B

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