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What is the energy of a photon that emits a light of frequency #6.42 * 10^14# #Hz#?

1 Answer

May 21, 2016

We use the Planck relation, #E=hnu#, where #h# #=# #"Planck's constant"# #=# #6.626070040(81)xx10^(−34)J*s#

Explanation:

Thus #E# #=# #6.626070040(81)xx10^(−34)J*sxx6.42xx10^14*s^-1# #~=# #10^(-20) J#.

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