What is the end behavior of #f(x)=-3x^5-4x^2+3#?

1 Answer
Alan P.
Aug 30, 2017

#f(x)rarr+oo" as "xrarr-oo#
#f(x)rarr-oo" as "xrarr+oo#

Explanation:

When dealing with end behavior, only the term with the highest degree is significant (because as #xrarr+-oo# its magnitude will exceed those of all other terms).

As #xrarr-oo#
#color(white)("XXX")x^5rarr -oo#
and
#color(white)("XXX")-3x^5rarr +oo#

Asw #xrarr+oo#
#color(white)("XXX")x^5rarr +oo#
and
#color(white)("XXX")-3x^5rarr -oo#

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