What is the electric current produced when a voltage of $8 V$ is applied to a circuit with a resistance of $16 Omega$ ?

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Answer 1 · 2016-01-12T19:03:01

$I=0.5 A= 500 mA$

The Ohm's Rule is:

$R=V/I$

$:.I=V/R$

In this case:

$V= 8 V$
$R=16 Omega$

then

$I= cancel(8)^1/cancel(16)^2=1/2=0.5 A$

With A= Ampere measurement unit of I

Sometimes, in Electronic, is usally expressed as $[mA]$

$1mA=10^-3A$

$:.I=0.5 A= 500 mA$

What is the electric current produced when a voltage of 8 V8 V is applied to a circuit with a resistance of 16 Omega16 Omega?