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What is the dot product of #<1,0,-2 ># and #<-1,-4,1 >#?

1 Answer

Feb 20, 2016

#<1,0,-2>*<-1,-4,1>#=#(1xx(-1)+0xx(-4)+(-2)xx1)=-3#

Explanation:

The dot product of vectors #< x_1,y_1,z_1 ># and #< x_2,y_2,z_2 ># is #x_1x_2+y_1y_2+z_1z_2#.

In this case, #<1,0,-2>*<-1,-4,1>#=#(1xx(-1)+0xx(-4)+(-2)xx1)=-3.#

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