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What is the domain of #f(x) = (x^2 - x - 6) /( x^2 + x - 12)#?

1 Answer

Oct 7, 2015

Domain: #RR-{-4,+3}#

Explanation:

#f(x)=(x^2-x-6)/(x^2+x-12)#
is defined for all Real values of #x# except those that cause #x^2+x-12 = 0#

Since #(x^2+x-1) = (x+4)(x-3)#

#color(white)("XXX")x=-4# and #x=3#
cause #x^2+x-12=0#
and are therefore forbidden from the Domain of #f(x)#

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