What is the distance between the following polar coordinates?: # (-1,(pi)/2), (2,(15pi)/12) #

1 Answer
Elvin Jafarli
Mar 11, 2018

I left explanation, try to finish it

Explanation:

In Euclidean geometry, we have where dl is the distance, we have:
#dl^2# = #dx^2 + dy^2#

In polar coordinates:
x =# r*cos(theta)#
dx = #drcos(theta) - rsin(theta)d theta#

y = #r*sin(theta)#
dy = #drsin(theta) + rcos(theta)d theta#

Plug into the first formula and you get the answer:)

Distance between 2 coordinates in polar coordiantes is given by:
l = #sqrt((r_2-r_1)^2 + r^2(theta_1 - theta_2))#

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