What is the discriminant of x^2 + 8x + 16 = 0 and what does that mean?

1 Answer
MeneerNask
Jul 23, 2015

The expression is of the form Ax^2+Bx+C=0
where A=1,B=6,C=16

Explanation:

The discriminant is defined as D=B^2-4AC
If D>0 there are two solutions to the equation
If D=0 there is one solution
If D<0 there is no solution (in real numbers)

In your case D=8^2-4*1*16=0->one solution.

The equation can be written as (x+4)^2->x=-4

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