What is the derivative of #y=1/(4-x^2) #? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Monzur R. Feb 9, 2017 #dy/dx = (2x)/(4-x^2)^2# Explanation: #y =1/(4-x^2) = (4-x^2)^-1.# This can easily be differentiated using the chain rule #dy/dx = -1(4-x^2)^-2(-2x) = (2x)/(4-x^2)^2# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 10277 views around the world You can reuse this answer Creative Commons License