What is the derivative of #(x^3-3x^2+4)/x^2#?
1 Answer
May 8, 2016
Explanation:
Divide each term on the numerator by
#x^2#
#(x^3)/x^2-(3x^2)/x^2+4/x^2=x-3+4x^-2# now differentiating using the
#color(blue)" power rule "#
#rArrd/dx(x-3+4x^-2)=1-8x^-3=1-8/x^3#
