What is the derivative of this function # (1-sin(x))^(-1/2)#? Calculus Differentiating Trigonometric Functions Intuitive Approach to the derivative of y=sin(x) 1 Answer Alan N. Aug 19, 2016 #cosx/(2(1-sinx)^(3/2))# Explanation: #f(x) = (1-sinx)^(-1/2)# #f'(x) = -1/2(1-sinx)^(-3/2) * d/dx(1-sinx)# (Power rule and Chain rule) #f'(x) = -1/2(1-sinx)^(-3/2) * (0-cosx)# #f'(x) = cosx/(2(1-sinx)^(3/2))# Answer link Related questions What is the derivative of #-sin(x)#? What is the derivative of #sin(2x)#? How do I find the derivative of #y=sin(2x) - 2sin(x)#? How do you find the second derivative of #y=2sin3x-5sin6x#? How do you compute #d/dx 3sinh(3/x)#? How do you find the derivative #y=xsinx + cosx#? What is the derivative of #sin(x^2y^2)#? What is #f'(-pi/3)# when you are given #f(x)=sin^7(x)#? How do you find the fist and second derivative of #pi*sin(pix)#? If f(x)= 2x sin(x) cos(x), how do you find f'(x)? See all questions in Intuitive Approach to the derivative of y=sin(x) Impact of this question 3750 views around the world You can reuse this answer Creative Commons License