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What is the derivative of #(tanx)^-1#?

1 Answer

Mar 8, 2018

#-csc^2(x)#

Explanation:

We have:

#d/dx((tan(x))^-1)#

Using, #(tan(x))^-1=cot(x)#, we get

#d/dx(cot(x))#

#=-csc^2(x)#

Source:

http://www.math.com/tables/derivatives/more/trig.htm

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