What is the derivative of #tan^5(x)#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer maganbhai P. Mar 21, 2018 #y=tan^5x=(tanx)^5=>dy/dx=5(tanx)^4d/(dx)(tanx)# #=>dy/dx=5tan^4x*sec^2x# Explanation: Let, #y=tan^5x=(tanx)^5# We take, #y=u^5,# where, #u=tanx# #=>(dy)/(du)=5u^4 and (du)/(dx)=sec^2x# Applying chain rule #dy/dx=dy/(du)*(du)/dx# #=>dy/dx=5u^4*sec^2x# #=>dy/dx=5(tanx)^4*sec^2x# #=>dy/dx=5tan^4xsec^2x# Answer link Related questions What is the derivative of #y=cos(x)# ? What is the derivative of #y=tan(x)# ? How do you find the 108th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x)# from first principle? How do you find the derivative of #y=cos(x^2)# ? How do you find the derivative of #y=e^x cos(x)# ? How do you find the derivative of #y=x^cos(x)#? How do you find the second derivative of #y=cos(x^2)# ? How do you find the 50th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x^2)# ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 12829 views around the world You can reuse this answer Creative Commons License