What is the derivative of #tan(3x+1)#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer ali ergin May 30, 2016 #y'=3(1+tan^2(3x+1))# Explanation: #y=tan(3x+1)# #"let 3x+1=u :"# #y=tan u# #y^'=u^'*(1+tan^2u)# #u^'=3# #y'=3(1+tan^2(3x+1))# Answer link Related questions What is the derivative of #y=cos(x)# ? What is the derivative of #y=tan(x)# ? How do you find the 108th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x)# from first principle? How do you find the derivative of #y=cos(x^2)# ? How do you find the derivative of #y=e^x cos(x)# ? How do you find the derivative of #y=x^cos(x)#? How do you find the second derivative of #y=cos(x^2)# ? How do you find the 50th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x^2)# ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 5190 views around the world You can reuse this answer Creative Commons License