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What is the derivative of # tan^3(x^4)#?

1 Answer

Apr 18, 2018

#dy/dx=12tan^2(x^4)sec^2(x^4)x^3#

Explanation:

#y=tan^3(x^4)#

#dy/dx=d/dx[tan^3(x^4)]=3tan^(3-1)(x^4)*d/dx[tan(x^4)]=3tan^2(x^4)(sec^2(x^4)d/dx[x^4])=12tan^2(x^4)sec^2(x^4)x^3#

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