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What is the derivative of # tan^2x secx#?

1 Answer

Shwetank Mauria

Jun 30, 2016

#d/(dx)tan^2xsecx=tanxsecx(2+3tan^2x)#

Explanation:

#d/(dx)tan^2xsecx#

= #2tanxsec^2x xxsecx+tan^2x xxsecxtanx#

= #tanxsecx(2sec^2x+tan^2x)#

= #tanxsecx(2(1+tan^2x)+tan^2x)#

= #tanxsecx(2+3tan^2x)#

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