What is the derivative of # tan^2x#?

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Answer 1 · 2018-05-25T23:49:23

#(dy)/(dx)= 2tanxsec^2x#

Let #y=tan^2x#

Let #u=tanx#

#(du)/(dx)=sec^2x#

Since #y=tan^2x#

Then #y=u^2#

#(dy)/(du)=2u#

#(dy)/(dx)=(dy)/(du)times(du)/(dx)#

#(dy)/(dx)=2utimessec^2x#

#(dy)/(dx)=2tanxsec^2x#