What is the derivative of # tan^-1(x^2)#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Leland Adriano Alejandro Jan 17, 2016 #d/dx(tan^-1 (x^2))=(2x)/(1+x^4)# Explanation: the formula #d/dx(Tan ^-1 u)=1/(1+u^2)*(du)/dx# Let #u=x^2# #d/dx(Tan ^-1 x^2)=1/(1+(x^2)^2)*(d/dx(x^2))# #d/dx(Tan ^-1 x^2)=(1/(1+(x^4))*2x)# #d/dx(tan^-1 (x^2))=(2x)/(1+x^4)# Just follow the formula Answer link Related questions What is the derivative of #y=cos(x)# ? What is the derivative of #y=tan(x)# ? How do you find the 108th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x)# from first principle? How do you find the derivative of #y=cos(x^2)# ? How do you find the derivative of #y=e^x cos(x)# ? How do you find the derivative of #y=x^cos(x)#? How do you find the second derivative of #y=cos(x^2)# ? How do you find the 50th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x^2)# ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 2070 views around the world You can reuse this answer Creative Commons License