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What is the derivative of #tan^(-1)(x^2)#?

1 Answer

Mar 8, 2017

#y '= (2x)/(1 + x^4)#

Explanation:

Use #(tan^-1(u))' = (u')/(1+u^2)#

Let #u = x^2#, #u' = 2x#

#y ' = (2x)/(1 + (x^2)^2) = (2x)/(1 + x^4)#

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