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What is the derivative of #sin^2(x)cos^2(x)#?

1 Answer

Jun 22, 2016

#(sin 4x)/2#

Explanation:

#sin(x)cos(x) = (sin 2x)/2#
#\implies sin^2(x)cos^2(x) = (sin^2 2x)/4#

#((sin^2 2x)/4)' = 1/4 (2 sin 2x cos 2x (2) ) = sin 2x cos 2x = (sin 4x)/2#

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