What is the derivative of #sin^2(x)cos^2(x)#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer ali ergin May 26, 2016 #d f(x)/(d x)=2sinx*cos^3x-2cosx*sin^3 x# Explanation: #f(x)=sin^2 x*cos^2 x# #d f(x)/(d x)=(sin^2 x)^'*cos^2x+(cos^2x)^'*sin^2 x# #d f(x)/(d x)=2 sin x*cos x*cos^2 x-2 cos x*sin x*sin^2 x# #d f(x)/(d x)=2sinx*cos^3x-2cosx*sin^3 x# Answer link Related questions What is the derivative of #y=cos(x)# ? What is the derivative of #y=tan(x)# ? How do you find the 108th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x)# from first principle? How do you find the derivative of #y=cos(x^2)# ? How do you find the derivative of #y=e^x cos(x)# ? How do you find the derivative of #y=x^cos(x)#? How do you find the second derivative of #y=cos(x^2)# ? How do you find the 50th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x^2)# ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 3834 views around the world You can reuse this answer Creative Commons License