What is the derivative of #g(w)= 1/(2^w+e^w)#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Sonnhard Jun 10, 2018 #-(2^wln(2)+e^w)/(2^w+e^w)^2# Explanation: Writing #g(w)=(2^w+e^w)^(-1)# so we get #g'(w)=(-1)(2^w+e^w)^(-2)(2^wln(2)+e^w)# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 1423 views around the world You can reuse this answer Creative Commons License