What is the derivative of g(w)= 1/(2^w+e^w)? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Sonnhard Jun 10, 2018 -(2^wln(2)+e^w)/(2^w+e^w)^2 Explanation: Writing g(w)=(2^w+e^w)^(-1) so we get g'(w)=(-1)(2^w+e^w)^(-2)(2^wln(2)+e^w) Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate y=(2x^4-3x)/(4x-1)? How do you use the quotient rule to differentiate y=cos(x)/ln(x)? How do you use the quotient rule to find the derivative of y=tan(x) ? How do you use the quotient rule to find the derivative of y=x/(x^2+1) ? How do you use the quotient rule to find the derivative of y=(e^x+1)/(e^x-1) ? How do you use the quotient rule to find the derivative of y=(x-sqrt(x))/(x^(1/3)) ? How do you use the quotient rule to find the derivative of y=x/(3+e^x) ? See all questions in Quotient Rule Impact of this question 1468 views around the world You can reuse this answer Creative Commons License