What is the derivative of # f(x)= tan 2x^2#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Michael Feb 24, 2016 #f'(x)=4xsec^2(2x^2)# Explanation: #f(x)=tan(2x^2)# Applying the chain rule #rArr# #f'(x)=sec^2(2x^2)xx4x# #=4xsec^2(2x^2)# Answer link Related questions What is the derivative of #y=cos(x)# ? What is the derivative of #y=tan(x)# ? How do you find the 108th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x)# from first principle? How do you find the derivative of #y=cos(x^2)# ? How do you find the derivative of #y=e^x cos(x)# ? How do you find the derivative of #y=x^cos(x)#? How do you find the second derivative of #y=cos(x^2)# ? How do you find the 50th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x^2)# ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 1525 views around the world You can reuse this answer Creative Commons License