What is the derivative of $-e^(3x^2)$ ?

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Answer 1 · 2018-04-19T17:45:01

$dy/dx=-6xe^(3x^2)$

By using chain rule for the function of function concept

$y=-e^(3x)^2)$

$y=-e^t$

$dy/dx=-e^t(dt)/(dx)$

$t=3x^2$

$t=3u$

$u=x^2$

$(du)/(dx)=2x$

$(dt)/(dx)=3)du)/(dx)$

$3(du/(dx)=3xx2x$

$(dt)/(dx)=3xx2x$

$3xx2x=6x$

$(dt)/(dx)=6x$

$dy/dx=-e^t(dt)/(dx)$

$dy/dx=-e^(3x^2)(6x)$

$dy/dx=-6xe^(3x^2)$

What is the derivative of -e^(3x^2)-e^(3x^2)?