How do you find the derivative of y=e^(1/x)y=e1x?
1 Answer
Jul 30, 2014
y'=-e^(1/x)/(x^2) Explanation :
Using Chain Rule,
Suppose,
y=e^f(x) then,
y'=e^f(x)*f'(x) Similarly following for the
y=e^(1/x)
y'=e^(1/x)*(1/x)'
y'=e^(1/x)*(-1/x^2)
y'=-e^(1/x)/(x^2)