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What is the derivative of #-1/(sin(x)^2)#?

1 Answer

Dec 26, 2016

#d/(dx) (-1/sin^2x) = (2cosx)/(sin^3x)#

Explanation:

Based on the chain rule:

#d/(dx) (-1/sin^x) = d/(dsinx) (-1/sin^2x) * (dsinx)/(dx)= 2/(sin^3x)cosx#

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