What is the cross product of <3,5,8> and <9,3,1>?

1 Answer
Mar 5, 2016

axb=19i69j+36k

Explanation:

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a=<3,5,8> b=<9,3,1>
axb=i(524)j(3+72)+k(9+45)
axb=19i69j+36k