What is the cross product of [0,8,5] and [1,2,-4] ?

1 Answer
Apr 1, 2016

[0,8,5] xx [1,2,-4] = [-42,5,-8]

Explanation:

The cross product of vecA and vecB is given by

vecA xx vecB = ||vecA|| * ||vecB|| * sin(theta) hatn,

where theta is the positive angle between vecA and vecB, and hatn is a unit vector with direction given by the right hand rule.

For the unit vectors hati, hatj and hatk in the directions of x, y and z respectively,

color(white)( (color(black){hati xx hati = vec0}, color(black){qquad hati xx hatj = hatk}, color(black){qquad hati xx hatk = -hatj}), (color(black){hatj xx hati = -hatk}, color(black){qquad hatj xx hatj = vec0}, color(black){qquad hatj xx hatk = hati}), (color(black){hatk xx hati = hatj}, color(black){qquad hatk xx hatj = -hati}, color(black){qquad hatk xx hatk = vec0}))

Also, cross product is distributive, which means

vecA xx (vecB + vecC) = vecA xx vecB + vecA xx vecC.

For this question,

[0,8,5] xx [1,2,-4]

= (8hatj + 5hatk) xx (hati + 2hatj - 4hatk)

= color(white)( (color(black){qquad 8hatj xx hati + 8hatj xx 2hatj + 8hatj xx (-4hatk)}), (color(black){+5hatk xx hati + 5hatk xx 2hatj + 5hatk xx (-4hatk)}) )

= color(white)( (color(black){-8hatk + 16(vec0) - 32hati}), (color(black){qquad +5hatj - quad 10hati quad - 20(vec0)}) )

= -42hati + 5hatj - 8hatk

= [-42,5,-8]