What is the concentration of nitrate ions in a 3.79M Mg(NO_3)_2Mg(NO3)2 solution?

1 Answer
anor277
Nov 30, 2015

If the solution has a concentration of 3.793.79 molmol L^-1L−1 in Mg(NO_3)_2Mg(NO3)2, then the concentration of the nitrate is twice this value.

Explanation:

Mg(NO_3)_2(s) rarr Mg^(2+) + 2NO_3^-Mg(NO3)2(s)→Mg2++2NO−3

[Mg^(2+)] = 3.79 mol*L^-1; [NO_3^-] = ??[Mg2+]=3.79mol⋅L−1;[NO−3]=??

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