What is the concentration of a solution, in parts per million, if 0.02 gram of $Na_3PO_4$ is dissolved?

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Answer 1 · 2016-04-28T18:31:51

$1$ $"ppm"$ $=$ $1*mg*L^-1$ . You have not given us a volume

A $"ppm"$ is so called because $1$ $L$ of water has a mass of $1$ $kg$ , i.e. $10^6$ $mg$ .

So if you have $0.020$ $g$ , you have $20xx10^-3*g$ , that is $20$ $mg$ or (!!IF THERE IS ONE LITRE OF SOLUTION!!) $20$ $"ppm"$ .

What is the concentration of a solution, in parts per million, if 0.02 gram of Na_3PO_4Na_3PO_4 is dissolved?