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What is the concentration if #.358# #g# of #NaNO_3# is present in #555# #mL# of water?

1 Answer

Dec 8, 2015

#7.59xx10^(-3) mol*L^-1# in sodium nitrate

Explanation:

Concentration here is simply (amount of substance)/(volume of solution).

So #(0.358*cancel(g))/(85.00*cancel(g)*mol^-1)# #xx# #1/(555xx10^(-3)*L)# #=# #??*mol*L^-1#

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