What is the balanced net ionic equation for $K_{2} S O_{4} (a q) + C a l_{2} (a q) \to C a S O_{4} (s) + K I (a q)$ $K_2SO_4(aq) + Cal_2(aq) -> CaSO_4(s) + KI(aq)$ ?

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What is the balanced net ionic equation for $K_{2} S O_{4} (a q) + C a l_{2} (a q) \to C a S O_{4} (s) + K I (a q)$ $K_2SO_4(aq) + Cal_2(aq) -> CaSO_4(s) + KI(aq)$ ?

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Answer 1 · 2017-03-08T06:36:56

$C a^{2 +} + S O_{4}^{2 -} \to C a S O_{4} (s) ⏐ ⏐ ↓$ $Ca^(2+) + SO_4^(2-) rarr CaSO_4(s)darr$

Explanation:

The net ionic equation represents MACROSCOPIC chemical change, which is here the precipitation of (reasonably) insoluble $calcium sulfate$ $"calcium sulfate"$ .

The potassium, and iodide ions are along for the ride, and remain is solution as aquated ions. And thus they are not included in the net ionic equation.

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What is the balanced net ionic equation for $K_{2} S O_{4} (a q) + C a l_{2} (a q) \to C a S O_{4} (s) + K I (a q)$ $K_2SO_4(aq) + Cal_2(aq) -> CaSO_4(s) + KI(aq)$ ?

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What is the balanced net ionic equation for K_2SO_4(aq) + Cal_2(aq) -> CaSO_4(s) + KI(aq)K2SO4(aq)+Cal2(aq)→CaSO4(s)+KI(aq)K_2SO_4(aq) + Cal_2(aq) -> CaSO_4(s) + KI(aq)?

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What is the balanced net ionic equation for $K_{2} S O_{4} (a q) + C a l_{2} (a q) \to C a S O_{4} (s) + K I (a q)$ $K_2SO_4(aq) + Cal_2(aq) -> CaSO_4(s) + KI(aq)$ ?