What is the axis of symmetry and vertex for the graph #y=x^(2)-2x-15#?
1 Answer
Apr 6, 2017
Explanation:
Use the method of
#color(blue)"completing the square"#
#• " add " (1/2" coefficient of x-term")^2#
#"that is " ((-2)/2)^2=1#
#rArry=(x^2-2xcolor(red)(+1))color(red)(-1)-15#
#rArry=(x-1)^2-16# The equation in
#color(blue)"vertex form"# is.
#• y=a(x-h)^2+k# where#(h,k)# are the coordinates of the vertex.
#"here " h=1" and " k=-16#
#rArr" vertex " =(1,-16)# The axis of symmetry passes through the vertex and is vertical.
#rArr"axis of symmetry is " x=1#
graph{(y-x^2+2x+15)(y+1000x-1000)=0 [-65.85, 65.85, -32.8, 33.05]}
