What is the axis of symmetry and vertex for the graph #y= -x^2 + 1#?

1 Answer
Shwetank Mauria
Apr 8, 2017

Axis of symmetry is #x=0# (#y#-axis) and vertex is #(0,1)#

Explanation:

The axis of symmetry of #(y-k)=a(x-h)^2# is #x-h=0# and vertex is #(h,k)#.

As #y=-x^2+1# can be written as

#(y-1)=-1(x-0)^2#

hence axis of symmetry is #x-0=0# i.e. #x=0# (#y#-axis) and vertex is #(0,1)#

graph{-x^2+1 [-10.29, 9.71, -6.44, 3.56]}

Note: The axis of symmetry of #(x-h)=a(y-k)^2# is #y-k=0# and vertex is #(h,k)#.

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