What is the axis of symmetry and vertex for the graph #y=x^2#?

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Answer 1 · 2016-05-23T20:28:58

See the explanation

Consider the standard equation of #y=ax^2+bx+c#

If #a# is positive then the graph is of shape #uu#

If #a# is negative then the graph is of shape #nn#

#color(blue)("In your equation "a=+1" so the graph is of shape "uu)#

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
The #bx# term moves the graph left or right from the y axis.

In your equation #b=0# ( there is no #bx# term)

#color(blue)("In your graph axis of symmetry is the y axis")#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The constant of #c# is the y intercept.

In your equation #c=0# so the y-intercept is the vertex as the axis of symmetry is the y axis

#color(blue)("In your equation the vertex "->(x,y)->(0,0))#